Let (a) Approximate ln(1 - x) with a third degree Taylor polynomial expanded about x = 0 Using this.

Let (a) Approximate ln(1 - x) with a third degree Taylor polynomial expanded about x = 0 Using this approximation, what value should you assign to f(0)? (b) Using MATLAB, plot f(x) for -10-15 = x = 10-15. What value does MATLAB assign to f(x) for x very near zero? The interval where the function is zero is not symmetric about x = 0. Why? Also, does this also explain why there are more oscillations on the right (x > 0) than on the left (x <> (c) Using MATLAB, plot ln(1-x) for -5×10 - 15 = x = 5×10 - 15 . The graph should resemble steps with the step containing x = 0 corresponding to the value of ln(1) = 0. As x increases from x = 0, what determines the value of the first nonzero step? How do these steps explain the oscillations seen in the plot for part (b)?